Ring Bicycle

Calculating the moment of inertia of a bicycle wheel with 8 spokes around a wheel rotating around its center?

Calculate the moment of inertia of a bicycle wheel (with 8 spokes (thin rods) evenly spaced around the wheel) rotating around its center. Approximate the tire as a thin ring.

the mass of the wheel I'll call K (for Ksyrium)
The mass of a single spoke I'll call t (for titanium)

The diameter of the wheel is 0.7m or 70 cm

I of a thin ring is MR^2
so the tire and rim is K*0.35^2

I of a rod supported on one end is
1/3*M*L^2

Each spoke (assuming no hub diameter) is
t*.35^2/3

So the moment of inertia for the whole assembly is
(K+8*t/3)*.35^2

j

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